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Comment by tmonteil for You should be able to just check if it has no...

The `Symbolic Ring` is quite unpredictible, so that you may lose some opportunities, for example: sage: expr = integral(exp(-cos(x)), x, 0, 1) sage: expr integrate(e^(-cos(x)), x, 0, 1) sage:...

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Comment by petropolis for You should be able to just check if it has no...

I woul prefer your method to the try/except method. I will wait to see if someone can make it watertight.

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Answer by Eviatar Bach for Context: I want to evaluate a symbolic expression...

You should be able to just check if it has no variables. def is_numerically_evaluable(expr): return not expr.variables() Then: sage: is_numerically_evaluable(sin(1)) True sage:...

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Answer by tmonteil for Context: I want to evaluate a symbolic expression...

Python (therefore Sage) offers a try/except system to handle exceptions, see [this page](http://docs.python.org/2/tutorial/errors.html) for more details. In your case, you can write something like:...

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How to check if a symbolic expression is numerically evaluable?

Context: I want to evaluate a symbolic expression numerically; however sometimes this expression still depends on some symbolic parameters not yet assigned a value. Question: What is the best way to...

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